EXAMPLE 1: | EXAMPLE 2: |
Given:
| The points (-4, 0) and (4, -2) lie on a line. |
|
Given:
| The point (-1, 3) lies on a line with a slope of 3. | |
Mark these two points on the plane. |
Mark the point (-1, 3) on the plane. Since the slope is 3, rise up 3 units, run across 1 unit, and mark the point (0, 6). This point will also lie on the line. |
Draw the line passing through these two points. |
Draw the line passing through these two points. |
|
|
EXAMPLE 1: | EXAMPLE 2: |
You can compute the slope of this line using the slope equation:
where (x1, x2) and (y1, y2) represent the coordinates of two points lying on the line.
Recall that the two points were (-4, 0) and (4, -2). This gives:
m = |
-2 - 0
4 - (-4) |
= | -2
8 |
= | -1
4 |
|
For this example, you are given the slope of the line, m = 3, so no computation is necessary. |
Check with the above graph to verify that the slope is -1/ 4.
|
You now have enough information to fill in the point-slope formula:
| Enter this information into the point-slope formula. Recall that the point given was (-1, 3).
|
y - (-2) | = | -(1/4)(x - 4) |
y + 2 | = | -(1/4)x + 1 |
y | = | -(1/4)x - 1 |
|
y - 3 | = | 3(x - (-1)) |
y - 3 | = | 3(x + 1) |
y - 3 | = | 3x + 3 |
y | = | 3x + 6 |
|
The equation of the line is y = -(1/4)x - 1.
| The equation of the line is y = 3x + 6
|